PCAP 31 03 PCAP Certified Associate Python Programmer · Free Practice Question Easy
Question 37
Q466 - Operators
The expression:
'mike' > 'Mike'
is
-
A
erroneous
-
B
false
-
C
true
Reveal correct answer
Correct answer: C
Explanation
Topic: greater than operator string comparison
Try it yourself:
- print('mike' > 'Mike') # True
- print(ord('m')) # 109
- print(ord('M')) # 77
Explanation:
The ASCII code of m is greater than the ASCII code of M
Q466 (Please refer to this number, if you want to write me about this question.)
A. In Python, string comparison is not erroneous. The comparison between 'mike' and 'Mike' is valid and evaluates to true because the lowercase 'm' has a higher Unicode value than the uppercase 'M'.
B. The comparison between 'mike' and 'Mike' is based on the Unicode values of the characters in the strings. Since the lowercase 'm' has a higher Unicode value than the uppercase 'M', the expression 'mike' > 'Mike' is true in Python.
C. In Python, string comparison is case-sensitive. Therefore, when comparing the strings 'mike' and 'Mike', the lowercase 'm' in 'mike' has a higher Unicode value than the uppercase 'M' in 'Mike'. As a result, the expression 'mike' > 'Mike' evaluates to true.
Discussion
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