Question 54

Correct answers: C, D

print('123' in '1-2-3')        # False
# "123" is not a part of "1-2-3"
 
print(not 'a' in 'abc')        # False
# "a" is a part of "abc"
 
print('\n' in """
""")                           # True
# A newline character is a part of every multi-line string.
 
print(not ('a' not in 'abc'))  # True
print(not False) # True
# "a" is a part of "abc"
# Two times not and it is True again.

A.

The expression ('a' not in 'abc') evaluates to False because the character 'a' is present in the string 'abc'. The outer 'not' operator negates the result of the inner expression, making it True.

B.

The expression

'\n' in """
"""

evaluates to True because the newline character '\n' is found in the triple-quoted string.

C. The expression not 'a' in 'abc' evaluates to False because the character 'a' is found in the string 'abc'. The 'not' operator negates the result, making it False, and no exception is raised during this evaluation.

D. The expression '123' in '1-2-3' evaluates to False because the string '123' is not found as a substring in the string '1-2-3'. This comparison results in False without raising an exception.